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6r^2=7+2r
We move all terms to the left:
6r^2-(7+2r)=0
We add all the numbers together, and all the variables
6r^2-(2r+7)=0
We get rid of parentheses
6r^2-2r-7=0
a = 6; b = -2; c = -7;
Δ = b2-4ac
Δ = -22-4·6·(-7)
Δ = 172
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{172}=\sqrt{4*43}=\sqrt{4}*\sqrt{43}=2\sqrt{43}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{43}}{2*6}=\frac{2-2\sqrt{43}}{12} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{43}}{2*6}=\frac{2+2\sqrt{43}}{12} $
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